5p^2-p-130=0

Solution for 5p^2-p-130=0 equation:

5p^2-p-130=0

We add all the numbers together, and all the variables

5p^2-1p-130=0

a = 5; b = -1; c = -130;
Δ = b2-4ac
Δ = -12-4·5·(-130)
Δ = 2601
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$p_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$p_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{2601}=51$
$p_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-1)-51}{2*5}=\frac{-50}{10}
=-5
$
$p_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-1)+51}{2*5}=\frac{52}{10}
=5+1/5
$